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A281747 Smallest b > 1 such that p = prime(n) satisfies b^(p-1) == 1 (mod p^p). 1
5, 26, 1068, 82681, 5392282366, 11356596271444, 34451905517028761171, 340625514346676110671584, 308318432223607315018221180590, 8566187045843934976180705488213013173127, 1099862052702774330481800364074681495062836757, 8170421001593885871548404108552563632485969048059688187 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

a(n) is the element in row prime(n), column n of the table in A257833.

Is the sequence always nondecreasing, or stronger, is it always increasing?

For odd primes p, if c is a primitive root mod p^p then b == c^(p^(p-1)) (mod p^p) satisfies this. Thus a(n) < prime(n)^prime(n) for n > 1. - Robert Israel, Jan 30 2017

LINKS

Robert Israel, Table of n, a(n) for n = 1..76

W. Keller and J. Richstein, Solutions of the congruence a^(p-1) == 1 (mod p^r), Math. Comp. 74 (2005), 927-936.

MAPLE

f:= proc(p) local c, j;

c:= numtheory:-primroot(p^p);

min(seq(c &^ (j*p^(p-1)) mod p^p, j=1..p-2))

end proc:

5, seq(f(ithprime(i)), i=2..15); # Robert Israel, Jan 30 2017

MATHEMATICA

Table[b = 2; While[PowerMod[b, (# - 1), #^#] &@ Prime@ n != 1, b++]; b, {n, 4}] (* Michael De Vlieger, Jan 30 2017 *)

PROG

(PARI) a(n) = my(p=prime(n), b=2); while(Mod(b, p^p)^(p-1)!=1, b++); b

CROSSREFS

Cf. A257833.

Sequence in context: A118366 A226125 A132509 * A064489 A081089 A180928

Adjacent sequences: A281744 A281745 A281746 * A281748 A281749 A281750

KEYWORD

nonn,hard,more

AUTHOR

Felix Fröhlich, Jan 29 2017

EXTENSIONS

More terms from Robert Israel, Jan 30 2017

STATUS

approved

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Last modified December 1 17:32 EST 2022. Contains 358470 sequences. (Running on oeis4.)