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A280558 Numbers k such that (13*10^k + 89) / 3 is prime. 0

%I #11 Jan 17 2019 13:44:08

%S 1,2,3,6,10,12,18,34,42,61,76,85,94,178,348,451,1123,1455,2234,4519,

%T 7502,16036,24216,156522

%N Numbers k such that (13*10^k + 89) / 3 is prime.

%C For k>1, numbers such that the digit 4 followed by k-2 occurrences of the digit 3 followed by the digits 63 is prime (see Example section).

%C a(25) > 2*10^5.

%H Makoto Kamada, <a href="https://stdkmd.net/nrr">Factorization of near-repdigit-related numbers</a>.

%H Makoto Kamada, <a href="https://stdkmd.net/nrr/prime/primedifficulty.txt">Search for 43w63.</a>

%e 3 is in this sequence because (13*10^3 + 89) / 3 = 4363 is prime.

%e Initial terms and primes associated:

%e a(1) = 1, 73;

%e a(2) = 2, 463;

%e a(3) = 3, 4363;

%e a(4) = 6, 4333363;

%e a(5) = 10, 43333333363; etc.

%t Select[Range[0, 100000], PrimeQ[(13*10^# + 89) / 3] &]

%o (PARI) is(n)=ispseudoprime((13*10^n + 89)/3) \\ _Charles R Greathouse IV_, Jun 13 2017

%Y Cf. A056654, A268448, A269303, A270339, A270613, A270831, A270890, A270929, A271269.

%K nonn,more,hard

%O 1,2

%A _Robert Price_, Jan 05 2017

%E a(24) from _Robert Price_, Sep 10 2018

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