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A279275
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Numbers k such that 2*k+1 and 5*k+1 are both pentagonal numbers (A000326).
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3
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500, 721525, 1040439075, 1500312425150, 2163449476627750, 3119692644984790875, 4498594630618591814525, 6486970337659364411754700, 9354206728310172863158463400, 13488759615252931609310092468625, 19450782010987999070452290181294375
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OFFSET
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1,1
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LINKS
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FORMULA
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a(n) = 5*((7-2*sqrt(10))*(721+228*sqrt(10))^(-n) + (7+2*sqrt(10))*(721+228*sqrt(10))^n - 14)/192.
a(n) = 1443*a(n-1) - 1443*a(n-2) + a(n-3) for n>3.
G.f.: 25*x*(20 + x) / ((1 - x)*(1 - 1442*x + x^2)).
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EXAMPLE
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500 is in the sequence because 2*500+1 = 1001 and 5*500+1 = 2501 are both pentagonal numbers.
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MATHEMATICA
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Table[Simplify[5 ((7 - 2 #) (721 + 228 #)^(-n) + (7 + 2 #) (721 + 228 #)^n - 14)/192 &@ Sqrt@ 10], {n, 11}] (* or *)
Rest@ CoefficientList[Series[25 x (20 + x)/((1 - x) (1 - 1442 x + x^2)), {x, 0, 11}], x] (* Michael De Vlieger, Dec 09 2016 *)
LinearRecurrence[{1443, -1443, 1}, {500, 721525, 1040439075}, 20] (* Harvey P. Dale, Apr 21 2020 *)
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PROG
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(PARI) isok(k) = ispolygonal(2*k+1, 5) & ispolygonal(5*k+1, 5)
(PARI) Vec(25*x*(20 + x) / ((1 - x)*(1 - 1442*x + x^2)) + O(x^30))
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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