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Numbers n having three parts in the symmetric representation of sigma(n).
9

%I #13 Dec 06 2016 22:16:00

%S 9,15,25,35,45,49,50,70,77,91,98,110,121,130,135,143,154,169,170,182,

%T 187,190,209,221,225,238,242,247,266,286,289,299,315,322,323,338,350,

%U 361,374,391,405,418,437,442,484,493,494,506,527,529,550,551,572,578,589,598,638,646,650,667,675,676,682

%N Numbers n having three parts in the symmetric representation of sigma(n).

%C Let n = 2^m * q with m >= 0 and q odd, let row(n) = floor(sqrt(8*n+1) - 1)/2), and let 1 = d_1 < ... < d_h <= row(n) < d_(h+1) < ... < d_k = q be the k odd divisors of n.

%C The symmetric representation of sigma(n) consists of 3 parts precisely when there is a unique i, 1 <= i < h, such that 2^(m+1) * d_i < d_(i+1) and d_h <= row(n) < 2^(m+1) * d_h.

%C This property of the odd divisors of n is equivalent to the n-th row of the irregular triangle of A249223 consisting of a block of positive numbers, followed by a block of zeros, followed in turn by a block of positive numbers, i.e., determining the first part and the left half of the center part of the symmetric representation of sigma(n), resulting in 3 parts.

%C Let n be the product of two primes p and q satisfying 2 < p < q < 2*p. Then n satisfies the property above so that the odd numbers in A087718 form a subsequence.

%e a(4) = 35 = 5*7 is in the sequence since 1 < 2 < 5 < row(35) = 7 < 10;

%e a(8) = 70 = 2*5*7 is in the sequence since 1 < 4 < 5 < row(70) = 11 < 20;

%e 140 = 4*5*7 is not in the sequence since 1 < 5 < 7 < 8 < row(140) = 16 < 20;

%e a(506) = 5950 = 2*25*7*17 is in the sequence since 1*4 < 5 is the only pair of odd divisors 1 < 5 < 7 < 17 < 25 < 35 < 85 < row(5950) = 108 satisfying the property (see A251820).

%t (* support functions are defined in A237048 and A262045 *)

%t segmentsSigma[n_] := Length[Select[SplitBy[a262045[n], #!=0&], First[#]!=0&]]

%t a279102[m_, n_] := Select[Range[m, n], segmentsSigma[#]==3&]

%t a279102[1, 700] (* sequence data *)

%t (* An equivalent, but slower computation is based on A237271 *)

%t a279102[m_, n_] := Select[Range[m, n], a237271[#]==3&]

%t a279102[1,700] (* sequence data *)

%Y Column 3 of A240062.

%Y Cf. A087718, A174973 (column 1), A237048, A237270, A237271, A237593, A239929 (column 2), A249223, A251820, A262045, A279102.

%K nonn

%O 1,1

%A _Hartmut F. W. Hoft_, Dec 06 2016