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a(n) = n+floor(n/(2/sqrt(Pi)-1)).
2

%I #16 Oct 02 2016 04:49:37

%S 8,17,26,35,43,52,61,70,79,87,96,105,114,123,131,140,149,158,166,175,

%T 184,193,202,210,219,228,237,246,254,263,272,281,290,298,307,316,325,

%U 333,342,351,360,369,377,386,395,404,413,421,430,439,448,457,465,474

%N a(n) = n+floor(n/(2/sqrt(Pi)-1)).

%H Carauleanu Marc, <a href="/A277052/b277052.txt">Table of n, a(n) for n = 1..4242</a>

%F a(n) = n + floor(n/(2/sqrt(Pi) - 1)).

%p A277052:=n->n+floor(n/(2/sqrt(Pi)-1)): seq(A277052(n), n=1..100); # _Wesley Ivan Hurt_, Sep 26 2016

%t f[n_] := n + Floor[n/(2/Sqrt[Pi]-1)]; Array[f, 100, 1]

%o (PARI) a(n) = n + floor(n/(2/sqrt(Pi)-1));

%Y Complement of A277050.

%Y Cf. A190732, A037086.

%K nonn,easy

%O 1,1

%A _Paulo Romero Zanconato Pinto_, Sep 26 2016