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n for which A277023(4n) is square, thus A277024(4n) is zero.
6

%I #8 Oct 04 2016 13:31:05

%S 0,1,2,3,4,5,6,9,10,12,14,15,17,18,20,21,23,24,26,28,30,31,33,34,35,

%T 36,37,39,40,41,42,44,45,48,51,52,54,55,56,57,58,60,63,66,68,69,70,71,

%U 72,74,78,80,81,84,88,90,91,93,95,96,98,99,102,105,107,108,110,111,112,114,117,118,120,121,123,126,129,131

%N n for which A277023(4n) is square, thus A277024(4n) is zero.

%C Indexing starts from zero because a(0)=0 is a special case in this sequence.

%H Antti Karttunen, <a href="/A277025/b277025.txt">Table of n, a(n) for n = 0..120</a>

%o (Scheme, with _Antti Karttunen_'s IntSeq-library)

%o (define A277025 (ZERO-POS 0 0 (lambda (n) (A277024 (* 4 n)))))

%Y Complement: A277026.

%Y Cf. A002828, A277015, A277016, A277024.

%K nonn

%O 0,3

%A _Antti Karttunen_, Oct 03 2016