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A276703
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Let A_n be the sequence defined in the same way as A159559 but with initial term prime(n), n>=2; a(n) = max(A_n(m) - A159559(m)), m>=2.
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5
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0, 4, 14, 14, 14, 70, 70, 70, 90, 90, 90, 90, 90, 90, 90, 90, 90, 121, 121, 121, 121, 121, 121, 126, 126, 126, 126, 126, 172, 172, 172, 172, 172, 172, 174, 174, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260, 2260
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OFFSET
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2,2
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COMMENTS
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LINKS
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EXAMPLE
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A_3(2)=5 and, by the definition of A159559 we have A_3(3)=7, A_3(4)=8, A_3(5)=11, A_3(6)=12, A_3(7)=13, A_3(8)=14, A_3(9)=15, A_3(10)=16, A_3(11)=17. Since A229019(3)=11, then comparing with the first 11 terms of A159559, we conclude that a(3)=A_3(5)-A_2(5)=4.
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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