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Simple self-inverse permutation of natural numbers: after a(0)=0, list each block of A261234(n) numbers in reverse order, from A261232(n) to A261233(1+n).
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%I #5 Sep 12 2016 17:03:16

%S 0,1,3,2,8,7,6,5,4,20,19,18,17,16,15,14,13,12,11,10,9,49,48,47,46,45,

%T 44,43,42,41,40,39,38,37,36,35,34,33,32,31,30,29,28,27,26,25,24,23,22,

%U 21,123,122,121,120,119,118,117,116,115,114,113,112,111,110,109,108,107,106,105,104,103,102,101,100,99,98,97,96

%N Simple self-inverse permutation of natural numbers: after a(0)=0, list each block of A261234(n) numbers in reverse order, from A261232(n) to A261233(1+n).

%C Maps between A276623 and A276624.

%H Antti Karttunen, <a href="/A276622/b276622.txt">Table of n, a(n) for n = 0..6250</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%F a(0) = 0; for n >= 1, a(n) = A261232(A276621(n)-1) + A261232(A276621(n)) - n - 1.

%o (Scheme) (define (A276622 n) (if (zero? n) n (+ (A261232 (+ -1 (A276621 n))) (- (A261232 (A276621 n)) n 1))))

%Y Cf. A261232, A276621, A276623, A276624.

%K nonn,base

%O 0,3

%A _Antti Karttunen_, Sep 11 2016