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60th powers: a(n) = n^60.
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%I #53 Sep 22 2025 16:01:25

%S 0,1,1152921504606846976,42391158275216203514294433201,

%T 1329227995784915872903807060280344576,

%U 867361737988403547205962240695953369140625,48873677980689257489322752273774603865660850176

%N 60th powers: a(n) = n^60.

%C Numbers which have square roots, cube roots, 4th, 5th and 6th roots.

%F a(n) = n^60.

%F a(n) = A122971(n)^2. - _Michel Marcus_, Sep 02 2016

%t Range[0, 6]^60 (* _Michael De Vlieger_, Sep 02 2016 *)

%o (PARI) a(n)=n^60 \\ _Charles R Greathouse IV_, Sep 01 2016

%o (SageMath) [n^60 for n in range(10)] # _Bruno Berselli_, Sep 03 2016

%o (Magma) [n^60: n in [0..10]]; // _Bruno Berselli_, Sep 03 2016

%Y Cf. A122971 (n^30), A183085 (subsequence).

%K nonn,easy

%O 0,3

%A _Bhushan Bade_, Sep 01 2016