login
a(n) = (2*n+1)^(2*(2*n+1)^2).
2

%I #38 Sep 30 2016 11:00:23

%S 1,387420489,88817841970012523233890533447265625,

%T 66009724686219550843768321818371771650147004059278069406814190436565131829325062449

%N a(n) = (2*n+1)^(2*(2*n+1)^2).

%C All terms are odd squares and are of the form k^k, where k = (2n+1)^2.

%H Christopher C. Capobianco, <a href="/A276274/b276274.txt">Table of n, a(n) for n = 0..20</a>

%e For n = 1, k = 3^2 = 9 and so a(1) = 3^(2*3^2) = 3^18 = 387420489.

%p A276274:=n->(2*n+1)^(2*(2*n+1)^2): seq(A276274(n), n=0..4); # _Wesley Ivan Hurt_, Sep 29 2016

%t Table[{x,(2x+1)^(2(2x+1)^2),{x,0,20}]

%o (PARI) a(n)=my(k=(2*n+1)^2); k^k \\ _Charles R Greathouse IV_, Aug 30 2016

%Y Subsequence of A000312, containing only the odd squares.

%Y Intersection of A000312 and A016754.

%K nonn

%O 0,2

%A _Christopher C. Capobianco_, Aug 26 2016