%I #12 Aug 21 2016 17:45:02
%S 0,1,6,7,12,13,120,121,126,127,132,133,240,241,246,247,252,253,360,
%T 361,366,367,372,373,5040,5041,5046,5047,5052,5053,5160,5161,5166,
%U 5167,5172,5173,5280,5281,5286,5287,5292,5293,5400,5401,5406,5407,5412,5413,10080,10081,10086,10087,10092,10093,10200,10201,10206,10207,10212,10213,10320,10321
%N Factorial base representation of n is aerated (and then converted back to decimal): for n = sum_{i=1..} digit(i)*i! (with each digit(i) <= i), a(n) = sum_{i=1..} digit(i)*(2i-1)!.
%C Here "aeration" means inserting zeros between the digits of factorial base representation of n. See the examples.
%H Antti Karttunen, <a href="/A276089/b276089.txt">Table of n, a(n) for n = 0..5039</a>
%H <a href="/index/Fa#facbase">Index entries for sequences related to factorial base representation</a>
%F When n = sum_{i=1..A084558(n)} d(i)*i! (which is unique representation as long as each d(i) <= i) then a(n) = sum_{i=1..A084558(n)} d(i)*(2i-1)!, where A084558(n) gives the length of factorial base representation of n.
%F Other identities. For all n >= 0:
%F A276090(a(n)) = n.
%e n A007623(n) "aerated" and converted back to decimal gives
%e a(n)
%e 0 0 0 0
%e 1 1 1 1
%e 2 10 100 6
%e 3 11 101 7
%e 4 20 200 12
%e 5 21 201 13
%e 6 100 10000 120
%e 7 101 10001 121
%e 8 110 10100 126
%e 9 111 10101 127
%e 10 120 10200 132
%e 11 121 10201 133
%e 12 200 20000 240
%e 13 201 20001 241
%e 14 210 20100 246
%e 15 211 20101 247
%e 16 220 20200 252
%e 17 221 20201 253
%e 18 300 30000 360
%e 19 301 30001 361
%e 20 310 30100 366
%e 21 311 30101 367
%e 22 320 30200 372
%e 23 321 30201 373
%o (Scheme)
%o ;; Standalone program:
%o (define (A276089 n) (let loop ((n n) (s 0) (f 1) (i 2) (j 2)) (if (zero? n) s (let ((d (modulo n i))) (loop (/ (- n d) i) (+ s (* f d)) (* j (+ 1 j) f) (+ 1 i) (+ 2 j))))))
%Y Cf. A000142, A007623, A084558
%Y Cf. A276090 (a left inverse).
%Y Cf. A275959 (subsequence).
%K nonn,base
%O 0,3
%A _Antti Karttunen_, Aug 19 2016