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A276054
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Sum of the asymmetry degrees of all compositions of n with parts in {1,2,4,6,8,10,...}.
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2
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0, 0, 0, 2, 2, 8, 16, 34, 72, 146, 294, 590, 1156, 2278, 4422, 8572, 16510, 31682, 60558, 115398, 219190, 415348, 784996, 1480600, 2786818, 5236078, 9821222, 18393268, 34397388, 64241880, 119831316, 223266154, 415532226, 772587316, 1435082052, 2663283782
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OFFSET
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0,4
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COMMENTS
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The asymmetry degree of a finite sequence of numbers is defined to be the number of pairs of symmetrically positioned distinct entries. Example: the asymmetry degree of (2,7,6,4,5,7,3) is 2, counting the pairs (2,3) and (6,5).
A sequence is palindromic if and only if its asymmetry degree is 0.
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REFERENCES
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S. Heubach and T. Mansour, Combinatorics of Compositions and Words, CRC Press, 2010.
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LINKS
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Index entries for linear recurrences with constant coefficients, signature (1,4,-1,-5,-3,-1,0,5,2,-4,1).
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FORMULA
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G.f.: g(z)=2*z^3*(1-z^2)(1+z^3-z^4)/((1+z^2)(1+z-z^3)(1-z-2z^2+z^3)^2). In the more general situation of compositions into a[1]<a[2]<a[3]<..., denoting F(z) = Sum(z^{a[j]},j>=1}, we have g(z)=(F(z)^2-F(z^2))/((1+F(z))(1-F(z))^2).
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EXAMPLE
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a(4) = 2 because the compositions of 4 with parts in {1,2,4,6,8,...} are 4, 22, 211, 121, 112, and 1111 and the sum of their asymmetry degrees is 0 + 0 + 1 + 0 + 1 + 0 = 2.
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MAPLE
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g:= 2*z^3*(1-z^2)*(1+z^3-z^4)/((1+z^2)*(1+z-z^3)*(1-z-2*z^2+z^3)^2): gser := series(g, z = 0, 45): seq(coeff(gser, z, n), n = 0 .. 40);
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MATHEMATICA
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Table[Total@ Map[Total, Map[Map[Boole[# >= 1] &, BitXor[Take[# - 1, Ceiling[Length[#]/2]], Reverse@ Take[# - 1, -Ceiling[Length[#]/2]]]] &, Flatten[Map[Permutations, DeleteCases[IntegerPartitions@ n, {___, a_, ___} /; Nor[a == 1, EvenQ@ a]]], 1]]], {n, 0, 23}] // Flatten (* or *)
CoefficientList[Series[2 x^3*(1 - x^2) (1 + x^3 - x^4)/((1 + x^2) (1 + x - x^3) (1 - x - 2 x^2 + x^3)^2), {x, 0, 35}], x] (* Michael De Vlieger, Aug 28 2016 *)
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PROG
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(PARI) concat(vector(3), Vec(2*x^3*(1-x^2)*(1+x^3-x^4)/((1+x^2)*(1+x-x^3)*(1-x-2*x^2+x^3)^2) + O(x^50))) \\ Colin Barker, Aug 28 2016
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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