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Following the successive antidiagonals in A065188, let the n-th queen appear in square (x(n),y(n)); sequence gives y(n).
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%I #16 Aug 25 2016 23:06:52

%S 1,3,2,5,4,9,6,11,8,7,13,15,10,19,12,14,22,25,16,27,18,17,29,31,20,21,

%T 35,37,23,39,24,41,26,28,45,48,30,32,51,53,33,34,56,58,36,38,60,63,40,

%U 66,42,43,70,44,72,74,46,76,47,78,50,49,82,84,52,86,54,89,55,57,92,59,96,98,61,100,62,102

%N Following the successive antidiagonals in A065188, let the n-th queen appear in square (x(n),y(n)); sequence gives y(n).

%C See A275899 for x(n).

%C This is a permutation of the natural numbers.

%C This assumes the indexing starts at 1. See A275901, A275902 if the indexing begins at 0.

%H N. J. A. Sloane, <a href="/A275900/b275900.txt">Table of n, a(n) for n = 1..7500</a>

%p See A275899.

%Y Cf. A065188, A275899, A275901, A275902.

%K nonn

%O 1,2

%A _N. J. A. Sloane_, Aug 24 2016