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The successive numbers of digits visible between two odd terms are given by the sequence itself.
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%I #6 Jun 02 2016 09:11:47

%S 0,1,3,2,5,4,6,8,7,10,9,12,100,11,14,16,13,18,20,22,15,24,26,28,30,17,

%T 32,34,102,19,36,38,40,42,44,21,46,48,50,104,23,52,54,56,58,60,62,25,

%U 64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94,96,98,106,108,110,112,114,116,118,120,122,124,126,128,130,132,134,136,138,140,142,144,1000,27,146,148,10000,29

%N The successive numbers of digits visible between two odd terms are given by the sequence itself.

%C The sequence starts with a(1)=0. It is then extended with the smallest integer not yet present and not leading to a contradiction. This sequence is a permutation of the integers >=0.

%e The first two odd terms that appear in the sequence are 1 and 3; between 1 and 3 there are 0 digits and this 0 corresponds to the starting 0 of the sequence.

%e The next odd term is 5; between 3 and 5 there is 1 digit [which is 2] and this 1 corresponds to the second term of the sequence.

%e The next odd term is 7; between 5 and 7 there are 3 digits [which are 4, 6 and 8] and this 3 corresponds to the third term of the sequence.

%e The next odd term is 9; between 7 and 9 there are 2 digits [which are 1 and 0] and this 2 corresponds to the fourth term of the sequence.

%e The next odd term is 11; between 9 and 11 there are 5 digits [which are 1, 2, 1, 0 and 0] and this 5 corresponds to the fifth term of the sequence. Etc.

%K nonn,base

%O 1,3

%A _Eric Angelini_, Jun 02 2016