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The union of hexagonal numbers (A000384) and centered 9-gonal numbers (A060544).
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%I #13 Jul 16 2016 07:32:00

%S 1,6,10,15,28,45,55,66,91,120,136,153,190,231,253,276,325,378,406,435,

%T 496,561,595,630,703,780,820,861,946,1035,1081,1128,1225,1326,1378,

%U 1431,1540,1653,1711,1770,1891,2016,2080,2145,2278,2415,2485,2556,2701,2850

%N The union of hexagonal numbers (A000384) and centered 9-gonal numbers (A060544).

%C The construction of the g.f. works basically as follows every third entry of A000384 equals every second entry of A060544, A000384(3n+1) = A060544(2n+1) = (3*n+1)*(6*n+1), which is an immediate consequence of their polynomial representations. So the sequence is the union of A000384 and the bisection 10, 55, 136, 253,... of A060544. Following Section 4.3 of Riordan's book "Combinatorial identities", subsampling and "aering" are done by replacing the independent variable of the g.f. by roots of the independent variable. So this sequence has rational g.f. because it is derived by regular interlacing of the two original sequences which also have rational g.f.'s. - _R. J. Mathar_, Jul 15 2016

%H Colin Barker, <a href="/A272398/b272398.txt">Table of n, a(n) for n = 1..1000</a>

%F a(4*n-3) = A272399(n).

%F Conjectures:

%F a(n) = (-1+(-1)^n-6*((-i)^n+i^n)*n+18*n^2)/16 where i is the imaginary unit.

%F a(n) = 2*a(n-1)-2*a(n-2)+2*a(n-3)-2*a(n-5)+2*a(n-6)-2*a(n-7)+a(n-8) for n>8.

%F G.f.: x*(1+4*x+5*x^3+6*x^4+x^5+x^6) / ((1-x)^3*(1+x)*(1+x^2)^2).

%Y Cf. A000384, A060544, A272399 (intersection).

%K nonn

%O 1,2

%A _Colin Barker_, Apr 28 2016