login

Reminder: The OEIS is hiring a new managing editor, and the application deadline is January 26.

Suspected permutation of natural numbers: a(n) = A255070(A269363(n)).
6

%I #8 Feb 28 2016 07:59:34

%S 1,2,3,5,4,7,9,11,6,8,12,17,13,10,21,23,19,14,18,16,28,20,15,35,30,41,

%T 24,39,27,22,42,25,36,26,47,40,29,34,32,33,37,55,38,51,49,43,59,67,57,

%U 68,58,69,64,65,75,119,76,66,74,52,46,44,50,87,90,56,71,111,45,85,60,72,54,77,104,79,99,88,95,48,53,78,102,82,31

%N Suspected permutation of natural numbers: a(n) = A255070(A269363(n)).

%C Lexicographically first injection of natural numbers beginning with a(1)=1 such that for all n >= 1, A091067(a(n))*A091067(a(n+1)) is a fibbinary number (A003714), i.e., has no adjacent 1's in its base-2 representation.

%H Antti Karttunen, <a href="/A269367/b269367.txt">Table of n, a(n) for n = 1..13217</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%F a(n) = A255070(A269363(n)).

%o (Scheme, with defineperm1-macro from _Antti Karttunen_'s IntSeq-library)

%o (defineperm1 (A269367 n) (A255070 (A269363 n)))

%o (define (A269368 n) (A269367 (- n))) ;; This returns inverse values of A269367 from its hidden cache.

%Y Left inverse: A269368 (also the right inverse if this is a permutation of natural numbers).

%Y Cf. A003714, A091067, A266121, A269361, A269363, A255070.

%K nonn,base

%O 1,2

%A _Antti Karttunen_, Feb 27 2016