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a(n) = n + (n base 2 regarded as a decimal number).
1

%I #38 Jul 08 2019 18:26:17

%S 0,2,12,14,104,106,116,118,1008,1010,1020,1022,1112,1114,1124,1126,

%T 10016,10018,10028,10030,10120,10122,10132,10134,11024,11026,11036,

%U 11038,11128,11130,11140,11142,100032,100034,100044,100046,100136,100138,100148,100150,101040

%N a(n) = n + (n base 2 regarded as a decimal number).

%C All terms in this sequence are even, because every even number produces an even binary number (ends with 0) and every odd number produces an odd binary number (ends with 1).

%H Isaac S. Friedman, <a href="/A269130/b269130.txt">Table of n, a(n) for n = 0..999</a>

%F a(n) = A007088(n) + n.

%e a(4) = convert_to_binary(4) + 4 = 100 + 4 = 104.

%t Table[n+FromDigits[IntegerDigits[n,2]],{n,0,40}] (* _Harvey P. Dale_, Jul 08 2019 *)

%o (PARI) a(n)=fromdigits(binary(n))+n \\ _Charles R Greathouse IV_, Feb 19 2016

%o (PARI) a(n) = subst(Pol(binary(n)), x, 10) + n \\ _Michel Marcus_, Feb 20 2016

%Y Cf. A000027 (counting numbers), A007088 (binary numbers).

%Y Cf. A127906 (multiplicated), A228071 (subtracted).

%K nonn,easy,base

%O 0,2

%A _Isaac S. Friedman_, Feb 19 2016