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Spelling out the characters (digits and commas) of the sequence and replacing letters A..Z with numbers 1..26 gives back the sequence.
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%I #8 Mar 30 2017 21:47:42

%S 20,23,15,26,5,18,15,3,15,13,13,1,20,23,15,20,8,18,5,5,3,15,13,13,1,

%T 15,14,5,6,9,22,5,3,15,13,13,1,20,23,15,19,9,24,3,15,13,13,1,6,9,22,5,

%U 3,15,13,13,1,15,14,5,5,9,7,8,20,3,15,13,13,1,15,14,5,6,9,22,5,3,15,13,13,1,20,8,18,5,5,3,15,13,13,1,15,14,5,6,9,22,5,3,15,13,13,1,15,14,5,20,8

%N Spelling out the characters (digits and commas) of the sequence and replacing letters A..Z with numbers 1..26 gives back the sequence.

%C A sequence with this property cannot start otherwise since 2 is the only digit equal to the first digit of the "code" (1-26) of the first letter of its English name.

%e Spelling out the sequence data character-wise yields "two zero comma two three comma one five ..."

%e Coding the letters A..Z by 1..26 yields again the sequence 20, 23, 15, 26, 5, 18, 15, 3, 15, 13, 13, ...

%o (PARI) concat(apply(f=t->Vec(Vecsmall(concat(concat(apply(English,digits(t))),"comma")))%32,f(20))) \\ See A052360 for English()

%Y Cf. A104059, A073029, A131744.

%K nonn,base,word

%O 1,1

%A _M. F. Hasler_, Feb 06 2016