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A267322 Expansion of (1 + x + x^2 + x^4 + 2*x^5)/(1 - x^3)^3. 1
1, 1, 1, 3, 4, 5, 6, 9, 12, 10, 16, 22, 15, 25, 35, 21, 36, 51, 28, 49, 70, 36, 64, 92, 45, 81, 117, 55, 100, 145, 66, 121, 176, 78, 144, 210, 91, 169, 247, 105, 196, 287, 120, 225, 330, 136, 256, 376, 153, 289, 425, 171, 324, 477, 190, 361, 532, 210, 400, 590, 231, 441, 651 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,4
COMMENTS
Triangular numbers alternating with squares and pentagonal numbers.
LINKS
Eric Weisstein's World of Mathematics, Triangular Number
Eric Weisstein's World of Mathematics, Square Number
Eric Weisstein's World of Mathematics, Pentagonal Number
FORMULA
G.f.: (1 + x + x^2 + x^4 + 2*x^5)/(1 - x^3)^3.
a(n) = 3*a(n-3) - 3*a(n-6) + a(n-9).
a(3k) = A000217(k+1), a(3k+1) = A000290(k+1), a(3k+2) = A000326(k+1).
Sum_{n>=0} 1/a(n) = 2 - Pi/sqrt(3) + Pi^2/6 + 3*log(3) = 5.1269715686...
a(n) = (floor(n/3) + 1)*((n+1)*floor(n/3) - 3*floor(n/3)^2 + 2)/2. - Bruno Berselli, Apr 08 2016
EXAMPLE
Illustration of initial terms:
==========================================================
n: 0 1 2 3 4 5 6 7 8
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o
o o
o o o o o o o o
o o o o o o o o o o o o o
o o o o o o o o o o o o o o o o o o
==========================================================
1 1 1 3 4 5 6 9 12
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MATHEMATICA
LinearRecurrence[{0, 0, 3, 0, 0, -3, 0, 0, 1}, {1, 1, 1, 3, 4, 5, 6, 9, 12}, 70]
Table[(Floor[n/3] + 1) ((n + 1) Floor[n/3] - 3 Floor[n/3]^2 + 2)/2, {n, 0, 70}] (* Bruno Berselli, Apr 08 2016 *)
CoefficientList[Series[(1+x+x^2+x^4+2x^5)/(1-x^3)^3, {x, 0, 70}], x] (* Harvey P. Dale, Dec 31 2023 *)
PROG
(PARI) x='x+O('x^99); Vec((1+x+x^2+x^4+2*x^5)/(1-x^3)^3) \\ Altug Alkan, Apr 07 2016
CROSSREFS
Sequence in context: A047427 A228235 A228895 * A218929 A088875 A022884
KEYWORD
nonn,easy
AUTHOR
Ilya Gutkovskiy, Apr 07 2016
STATUS
approved

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Last modified April 19 19:02 EDT 2024. Contains 371798 sequences. (Running on oeis4.)