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Numbers D such that D^2 = A^2 + B^3 + C^4 has more than two solutions in positive integers (A, B, C).
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%I #6 Feb 02 2016 03:36:21

%S 9,21,28,33,45,47,51,53,55,61,65,66,68,69,70,73,75,77,81,82,84,87,89,

%T 91,93,95,97,103,105,107,108,109,110,111,113,114,116,117,119,123,128,

%U 129,131,133,135,136,139,142,143,145,147,149,150,152,154,156,157,161

%N Numbers D such that D^2 = A^2 + B^3 + C^4 has more than two solutions in positive integers (A, B, C).

%C Subsequence of A256604.

%H Chai Wah Wu, <a href="/A267216/b267216.txt">Table of n, a(n) for n = 1..10000</a>

%e 9^2 = 1^2 + 4^3 + 2^4 = 4^2 + 4^3 + 1^4 = 8^2 + 1^3 + 2^4.

%e 21^2 = 11^2 + 4^3 + 4^4 = 12^2 + 6^3 + 3^4 = 19^2 + 4^3 + 2^4.

%Y Cf. A256604.

%K nonn

%O 1,1

%A _Chai Wah Wu_, Feb 01 2016