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Self-inverse permutation of nonnegative integers: a(n) = A264979(8*n) / 8.
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%I #11 May 24 2021 00:18:03

%S 0,1,8,7,6,5,4,3,2,9,10,71,62,53,44,35,26,17,72,89,80,61,52,43,34,25,

%T 16,63,88,79,70,51,42,33,24,15,54,87,78,69,60,41,32,23,14,45,86,77,68,

%U 59,50,31,22,13,36,85,76,67,58,49,40,21,12,27,84,75,66,57,48,39,30,11,18,83,74,65,56,47,38,29,20,81

%N Self-inverse permutation of nonnegative integers: a(n) = A264979(8*n) / 8.

%C It appears that A264979(m x) == 0 (mod m) for m = 2^k and m = 5*2^k, k >= 0, but not for other m. Is there a simple explanation? - _M. F. Hasler_, May 21 2021

%H Antti Karttunen, <a href="/A265338/b265338.txt">Table of n, a(n) for n = 0..7381</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%F a(n) = A264979(8*n) / 8.

%o (Scheme) (define (A265338 n) (/ (A264979 (* 8 n)) 8))

%Y Cf. A264979.

%Y Cf. also A264978.

%K nonn,base

%O 0,3

%A _Antti Karttunen_, Dec 07 2015