A264931 - OEIS

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A264931

a(n) = 1+2*3^4...[n-1]n where [n] is the n-th hyperoperator.

%I #14 Jan 11 2020 15:57:47

%S 1,3,7,163

%N a(n) = 1+2*3^4...[n-1]n where [n] is the n-th hyperoperator.

%C a[n]b is the square bracket notation for hyperoperation. See A054871 for more info.

%e a(1) = 1;

%e a(2) = 1+2 = 3;

%e a(3) = 1+2*3 = 7;

%e a(4) = 1+2*3^4 = 163;

%e a(5) = 1+2*3^4^^5 which is too big to be included.

%Y Cf. A054871, A254225, A254310.

%K nonn

%O 1,2

%A _Natan Arie Consigli_, Nov 29 2015