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%I #12 Sep 24 2015 01:40:24
%S 1,0,4,5,2,3,7,6,10,11,8,9,18,19,20,21,22,23,12,13,14,15,16,17,25,24,
%T 28,29,26,27,31,30,34,35,32,33,42,43,44,45,46,47,36,37,38,39,40,41,49,
%U 48,52,53,50,51,55,54,58,59,56,57,66,67,68,69,70,71,60,61,62,63,64,65,96,97,98,99,100,101
%N Row 1 of A261096.
%C Equally, column 1 of A261097.
%C Take the n-th (n>=0) permutation from the list A055089 (A195663), change 1 to 2 and 2 to 1 to get another permutation, and note its rank in the same list to obtain a(n).
%C Self-inverse permutation of nonnegative integers.
%H Antti Karttunen, <a href="/A261098/b261098.txt">Table of n, a(n) for n = 0..5039</a>
%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>
%F a(n) = A261096(1,n).
%F By conjugating related permutations:
%F a(n) = A060119(A261218(A060126(n))).
%e In A195663 the permutation with rank 12 is [1,3,4,2], and swapping the elements 1 and 2 we get permutation [2,3,4,1], which is listed in A195663 as the permutation with rank 18, thus a(12) = 18.
%Y Row 1 of A261096, column 1 of A261097.
%Y Cf. A055089, A195663.
%Y Cf. also A004442.
%Y Related permutations: A060119, A060126, A261218.
%K nonn
%O 0,3
%A _Antti Karttunen_, Aug 26 2015
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