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%I #4 Jul 14 2015 07:56:16
%S 48,91,91,256,214,256,557,594,594,557,956,1214,1680,1214,956,2131,
%T 2367,3825,3825,2367,2131,5088,5776,6714,7725,6714,5776,5088,10235,
%U 13366,16344,12664,12664,16344,13366,10235,20242,28064,42094,34917,25444,34917
%N T(n,k)=Number of (n+2)X(k+2) 0..1 arrays with each 3X3 subblock having clockwise perimeter pattern 00000001 00000011 or 00000111
%C Table starts
%C ....48.....91....256....557.....956.....2131.....5088....10235.....20242
%C ....91....214....594...1214....2367.....5776....13366....28064.....63014
%C ...256....594...1680...3825....6714....16344....42094....84761....173654
%C ...557...1214...3825...7725...12664....34917....89948...166473....353678
%C ...956...2367...6714..12664...25444....77061...185370...361576....898184
%C ..2131...5776..16344..34917...77061...251582...660896..1470739...4080236
%C ..5088..13366..42094..89948..185370...660896..1838884..3846432..10411860
%C .10235..28064..84761.166473..361576..1470739..3846432..7478945..22555298
%C .20242..63014.173654.353678..898184..4080236.10411860.22555298..76589120
%C .45355.147105.438404.964837.2496222.12463280.34278032.79843532.296873856
%H R. H. Hardin, <a href="/A260070/b260070.txt">Table of n, a(n) for n = 1..544</a>
%F Empirical for column k:
%F k=1: a(n) = a(n-1) +4*a(n-3) +5*a(n-4) -5*a(n-5) -2*a(n-6)
%F k=2: [order 11]
%F k=3: [order 17] for n>21
%F k=4: [order 21] for n>25
%F k=5: [order 39] for n>43
%F k=6: [order 69] for n>75
%e Some solutions for n=4 k=4
%e ..0..0..0..0..1..0....0..1..0..0..1..1....1..0..0..0..0..1....0..0..0..0..0..0
%e ..1..0..0..0..1..0....0..1..0..0..0..0....0..1..0..0..1..1....1..1..0..0..0..1
%e ..1..1..0..0..0..0....0..0..0..0..0..0....0..0..0..0..0..0....0..0..0..0..1..1
%e ..0..0..0..0..0..0....0..0..0..0..1..1....0..0..0..0..0..0....0..0..0..0..0..0
%e ..0..0..0..0..1..0....0..1..0..0..0..1....1..1..0..0..1..0....0..1..0..0..0..0
%e ..1..1..0..0..1..0....0..1..0..0..0..0....1..0..0..0..1..1....1..0..0..0..1..0
%K nonn,tabl
%O 1,1
%A _R. H. Hardin_, Jul 14 2015
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