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 A258756 a(n) = common difference giving the highest score in the game "Sequences" for a sequence with largest element n and as many elements as possible. 0
 1, 1, 2, 2, 3, 3, 4, 3, 5, 5, 4, 4, 7, 3, 4, 4, 3, 3, 4, 3, 3, 3, 3, 3, 3, 3, 4, 4, 3, 3, 4, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 (list; graph; refs; listen; history; text; internal format)
 OFFSET 3,3 COMMENTS The aim of the game is to find, in the given numbered tiles, arithmetic sequences of at least three elements. The score for a sequence is (max element)*(common difference ^ num elements). This sequence gives the common difference which produces the best score for a sequence with largest element n, and containing as many elements as possible. This sequence converges to 3, which must have something to do with the fact that log(x)/x is maximized at x=e. Is n=45 the last time a(n) is not 3? LINKS Table of n, a(n) for n=3..132. Christian Perfect, Sequences game PROG (Python) def score(n, step): ...return n*(step**(n//step+(1 if n%step!=0 else 0))) . def best(n): ...return max(range(1, (n-1)//2+1), key=lambda step:score(n, step)) CROSSREFS Sequence in context: A323636 A283367 A322528 * A127431 A289777 A182921 Adjacent sequences: A258753 A258754 A258755 * A258757 A258758 A258759 KEYWORD nonn,easy AUTHOR Christian Perfect, Jun 09 2015 STATUS approved

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Last modified February 28 09:08 EST 2024. Contains 370394 sequences. (Running on oeis4.)