A258692 Integers n such that n*(n + 2)*(n + 4) + 1 is a perfect square.

-4, -3, -2, 0, 1, 2, 8, 10, 18, 112, 1272

Offset

1,1

Comments

This sequence is finite as there are finitely many integer solutions to the elliptic curve y^2 = x(x + 2)(x + 4) + 1 = x^3 + 6x^2 + 8x + 1. The x values of the integer solutions are {-4, -3, -2, 0, 1, 2, 8, 10, 18, 112, 1272}. This equation has more integer and natural number solutions than the equation that defines sequence A121234.

Links

Table of n, a(n) for n=1..11.

Example

1 * 3 * 5 + 1 = 16 = 4^2, so 4 is in the sequence.
2 * 4 * 6 + 1 = 49 = 7^2, so 2 is in the sequence.
3 * 5 * 7 + 1 = 106 = 2 * 53, so 3 is not in the sequence.

Mathematica

Select[Range[-10, 100], IntegerQ[Sqrt[#(# + 2)(# + 4) + 1]] &] (* Alonso del Arte, Jun 12 2015 *)

Prog

(Magma) P<n> := PolynomialRing(Integers()); {x: x in Sort([ p[1] : p in IntegralPoints(EllipticCurve(n^3 + 6*n^2 + 8*n + 1)) ])};
(SageMath) [i[0] for i in EllipticCurve([0, 6, 0, 8, 1]).integral_points()] # Seiichi Manyama, Aug 26 2019

Crossrefs

Cf. A121234.

Sequence in context: A176863 A349989 A067017 * A067018 A200233 A373750

Adjacent sequences: A258689 A258690 A258691 * A258693 A258694 A258695

Keyword

sign,fini,full

Author

Morris Neene, Jun 12 2015

Status

approved