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Number of partitions of 2*n! into parts that are at most n.
5

%I #5 Jun 07 2015 06:19:54

%S 0,1,3,19,1033,1302311,74312057469,291484874476601933,

%T 109290159404495354765494065,5262212497884462986538879797523944401,

%U 42425405450182072688801993326226988336684453926401,72600595215718916449806606426629386781199080157371905867835756161

%N Number of partitions of 2*n! into parts that are at most n.

%H Vaclav Kotesovec, <a href="/A258669/b258669.txt">Table of n, a(n) for n = 0..31</a>

%H A. V. Sills and D. Zeilberger, <a href="http://arxiv.org/abs/1108.4391">Formulae for the number of partitions of n into at most m parts (using the quasi-polynomial ansatz)</a> (arXiv:1108.4391 [math.CO])

%F a(n) ~ n * 2^(n-1) * (n!)^(n-3).

%Y Cf. A236810, A237998, A238000, A258668, A258670, A258671.

%K nonn

%O 0,3

%A _Vaclav Kotesovec_, Jun 07 2015