login
Number of distinct primes dividing the number of partitions of n into distinct parts, a(n) = A001221(A000009(n)).
2

%I #7 Aug 19 2022 15:18:32

%S 0,0,0,1,1,1,1,1,2,1,2,2,2,2,2,1,1,2,2,2,1,2,1,2,2,2,3,2,3,1,2,3,4,2,

%T 1,3,2,3,2,2,3,4,3,4,2,1,2,4,4,3,3,2,3,2,3,3,2,4,3,3,3,2,3,2,2,4,3,3,

%U 2,3,1,2,2,4,3,2,4,3,2,4,2,4,2,2,2,3,2

%N Number of distinct primes dividing the number of partitions of n into distinct parts, a(n) = A001221(A000009(n)).

%H Giovanni Resta, <a href="/A258595/b258595.txt">Table of n, a(n) for n = 0..10000</a>

%F a(n) = A001221(A000009(n)).

%t PrimeNu @ PartitionsQ @ Range[0, 100]

%Y Cf. A000009, A001221, A258594.

%K nonn

%O 0,9

%A _Giovanni Resta_, Jun 04 2015