A257904 - OEIS

%I #9 Jun 11 2015 10:35:49

%S 3,1,2,-1,4,-2,5,-4,6,-3,7,-8,9,-6,8,-5,10,-11,12,-10,11,13,-21,14,

%T -12,15,-14,16,-15,18,-17,19,-13,17,-19,20,-16,21,-24,22,-20,23,-9,24,

%U -35,25,-22,26,-28,27,-23,28,-25,29,-27,30,-18,-7,31,-34,32,-26

%N Sequence (d(n)) generated by Algorithm (in Comments) with a(1) = 0 and d(1) = 2.

%C Algorithm:  For k >= 1, let  A(k) = {a(1), …, a(k)} and D(k) = {d(1), …, d(k)}.  Begin with k = 1 and nonnegative integers a(1) and d(1).  Let h be the least integer > -a(k) such that h is not in D(k) and a(k) + h is not in A(k).  Let a(k+1) = a(k) + h and d(k+1) = h.  Replace k by k+1 and repeat inductively.

%C Conjecture:  if a(1) is an nonnegative integer and d(1) is an integer, then (a(n)) is a permutation of the nonnegative integers (if a(1) = 0) or a permutation of the positive integers (if a(1) > 0).  Moreover, (d(n)) is a permutation of the integers if d(1) = 0, or of the nonzero integers if d(1) > 0.

%C See A257883 for a guide to related sequences.

%H Clark Kimberling, <a href="/A257904/b257904.txt">Table of n, a(n) for n = 1..1000</a>

%F a(k+1) - a(k) = d(k+1) for k >= 1.

%e a(1) = 0, d(1) = 2;

%e a(2) = 1, d(2) = 1;

%e a(3) = 4, d(3) = 3;

%e a(4) = 2, d(4) = -2.

%t a[1] = 0; d[1] = 3; k = 1; z = 10000; zz = 120;

%t A[k_] := Table[a[i], {i, 1, k}]; diff[k_] := Table[d[i], {i, 1, k}];

%t c[k_] := Complement[Range[-z, z], diff[k]];

%t T[k_] := -a[k] + Complement[Range[z], A[k]]

%t Table[{h = Min[Intersection[c[k], T[k]]], a[k + 1] = a[k] + h,

%t    d[k + 1] = h, k = k + 1}, {i, 1, zz}];

%t u = Table[a[k], {k, 1, zz}]  (* A257903 *)

%t Table[d[k], {k, 1, zz}]      (* A257904 *)

%Y Cf. A257903, A257883, A257705.

%K easy,sign

%O 1,1

%A _Clark Kimberling_, May 13 2015