%I #7 May 11 2015 13:53:32
%S 2,4,6,6,4,0,8,2,6,2,4,1,2,6,7,8,0,7,5,1,9,7,1,0,3,3,5,0,7,7,5,9,3,2,
%T 9,5,0,2,9,0,7,8,0,8,7,8,2,7,7,4,0,9,9,8,2,3,7,8,6,0,8,9,8,8,1,6,1,2,
%U 2,4,0,9,4,1,5,0,0,9,1,5,0,7,1,7,1,6,2,7,8,1,5,8,0,4,6,5,5,8,4,7,2,9,3,3,6
%N Decimal expansion of the unique real number a>0 such that the real part of li(-a) is zero.
%C As discussed in A257819, the real part of li(z) is a well behaved function for any real z, except for the singularity at z=+1. It has three roots: z=A070769 (the Soldner's constant), z=0, and z=-a. However, unlike in the other two cases, the imaginary part of li(-a) is not infinitesimal in the neighborhood of this root; it is described in A257822.
%H Stanislav Sykora, <a href="/A257821/b257821.txt">Table of n, a(n) for n = 1..2000</a>
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/LogarithmicIntegral.html">Logarithmic Integral</a>
%H Wikipedia, <a href="http://en.wikipedia.org/wiki/Logarithmic_integral_function">Logarithmic integral function</a>
%F Satisfies real(li(-a)) = 0.
%e 2.4664082624126780751971033507759329502907808782774099823786...
%t RealDigits[a/.FindRoot[Re[LogIntegral[-a]]==0,{a,2},WorkingPrecision->120]][[1]] (* _Vaclav Kotesovec_, May 11 2015 *)
%o (PARI) li(z) = {my(c=z+0.0*I); \\ If z is real, convert it to complex
%o if(imag(c)<0, return(-Pi*I-eint1(-log(c))),
%o return(+Pi*I-eint1(-log(c)))); }
%o a=-solve(x=-3,-1,real(li(x))) \\ Better use excess realprecision
%Y Cf. A070769, A257819, A257822.
%K nonn,cons
%O 1,1
%A _Stanislav Sykora_, May 11 2015
|