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a(n+1) = a(n) + smallest nonzero (and unused) integer embedded in a(n) as a contiguous subchain.
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%I #12 May 01 2015 14:41:40

%S 1,2,4,8,16,22,44,88,176,183,186,204,224,248,296,305,310,320,352,387,

%T 425,450,495,544,598,657,714,728,756,812,824,906,996,1092,1184,1195,

%U 1214,1235,1258,1316,1329,1358,1493

%N a(n+1) = a(n) + smallest nonzero (and unused) integer embedded in a(n) as a contiguous subchain.

%e If a(n)=1235, a(n+1) could only be 1235+1, or 1235+2, or 1235+3, or 1235+5, or 1235+12, or 1235+23, or 1235+35, or 1235+123, or 1235+235, or 1235+1235, depending on the numbers already used.

%e In fact, 1258 follows 1235 in the sequence, because 1235+23=1258, and 23 is the smallest subchain in 1235 that has not already been used up to this point (1,2,4,8,6,22,44,88,7,3, etc. are the numbers that have been used).

%Y See A257350 for a variant.

%K nonn,base

%O 1,2

%A _Jean-Marc Falcoz_, Apr 17 2015