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A256584
Integer areas of integer-sided triangles where at least one of the three altitudes is of perfect square length.
0
6, 12, 54, 96, 108, 126, 144, 180, 192, 216, 234, 240, 264, 270, 336, 360, 378, 408, 480, 486, 504, 522, 540, 594, 600, 744, 750, 756, 864, 900, 972, 990, 1008, 1026, 1116, 1134, 1224, 1296, 1350, 1386, 1404, 1494, 1500, 1536, 1584, 1620, 1656, 1728, 1800, 1872
OFFSET
1,1
COMMENTS
a(n) contains A210643.
There are triangles with rational square, for instance, with the area 144, we find for (a,b,c)=(6,50,52) the altitudes {Ha,Hb,Hc} = {72/13, 144/25, 48} but with the same area we find also for (a,b,c)=(18,20,34) the altitudes {Ha,Hb,Hc} = {144/17, 72/5, 16}.
The corresponding squares are 4, 4, 9, 16, 9, 9, 16, 9, 16, 36, 9, 16, 16, 36, 16, 9, 36, 16, 16, 36, 16, 36, 36, 36, 16, 16, 25, 36, 36, 36, 36, 36, 16, 36, 36, 36, 144, 144, 36, 36, 36, 36, 100, 64, 144, 36, 36, 36, 144, 36, ...
The subsequence of the primitive triangles are 6, 12, 126, 144, 180, 216, 234, ...
The area A of a triangle whose sides have lengths a, b, and c is given by Heron's formula: A = sqrt(s*(s-a)*(s-b)*(s-c)), where s = (a+b+c)/2.
The altitudes of a triangle with sides length a, b, c and area A have length given by Ha= 2A/a, Hb= 2A/b, Hc= 2A/c.
Properties of this sequence:
- The sequence is infinite because from de initial primitive triangle (3,4,5), the area A’ of the triangle (3*3^m, 4*3^m, 5*3^m) is also in the sequence where A’ = 6*3^2m and {Ha, Hb, Hc} = {4*3^m, 3^(m+1), (4*3^(m+1))/5}. The altitude Ha or Hb is square.
- There are three subsets of numbers included into a(n):
Case (i): A subset with right triangles (a,b,c) where a^2+b^2 = c^2 with area a2(n) = {6, 54, 96, 180, 240, 270, ...}
Case (ii): A subset with isosceles triangles of area a1(n)= {12, 108, 192, 360, 480, 540, ...} = 2*a1(n).
Case (iii): A subset with non-isosceles and non-right triangles of area a3(n)= {126, 144, 216, 234, 264, 336, ...}
-----------------------------------------------------------
| A | a | b | c | Ha | Hb | Hc |
-----------------------------------------------------------
| 6 | 3 | 4 | 5 | 12/5 | 3 | 4 |
| 12 | 5 | 5 | 6 | 4 | 24/5 | 24/5 |
| 54 | 9 | 12 | 15 | 36/5 | 9 | 12 |
| 96 | 12 | 16 | 20 | 48/5 | 12 | 16 |
| 108 | 15 | 15 | 24 | 9 | 72/5 | 72/5 |
| 126 | 15 | 28 | 41 | 252/41 | 9 | 84/5 |
| 144 | 18 | 20 | 34 | 144/17 | 72/5 | 16 |
| 180 | 9 | 40 | 41 | 360/41 | 9 | 40 |
| 192 | 20 | 20 | 24 | 16 | 96/5 | 96/5 |
| 216 | 12 | 39 | 45 | 48/5 | 144/13 | 36 |
| 234 | 15 | 41 | 52 | 9 | 468/41 | 156/5 |
| 240 | 16 | 30 | 34 | 240/17 | 16 | 30 |
| 264 | 33 | 34 | 65 | 528/65 | 264/17 | 16 |
LINKS
Eric Weisstein, Altitude
Eric Weisstein, Isosceles Triangle
Eric Weisstein, Right Triangle
EXAMPLE
1350 is in the sequence because the altitudes of the triangle (45, 60, 75) are (60, 45, 36).
MATHEMATICA
nn=200; lst={}; Do[s=(a+b+c)/2; If[IntegerQ[s], area2=s (s-a) (s-b) (s-c); If[0<area2&&IntegerQ[Sqrt[area2]]&&(IntegerQ[Sqrt[2*Sqrt[area2]/a]]||IntegerQ[Sqrt[2*Sqrt[area2]/b]]||IntegerQ[Sqrt[2*Sqrt[area2]/c]]), AppendTo[lst, Sqrt[area2]]]], {a, nn}, {b, a}, {c, b}]; Union[lst]
CROSSREFS
Cf. A210643.
Sequence in context: A226882 A214903 A372900 * A117866 A365691 A290999
KEYWORD
nonn
AUTHOR
Michel Lagneau, Apr 02 2015
STATUS
approved