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%I #11 Apr 04 2015 17:54:25
%S 1,4,9,2,25,3,49,12,6,5,132,8,169,7,10,18,289,16,399,15,14,11,529,30,
%T 20,13,24,21,841,27,961,36,22,17,28,32,1369,19,26,70,1681,35,1849,33,
%U 40,23,2209,54,42,45,34,39,2809,48,44,133,38,29,3481,50,3721,31
%N Inverse permutation to A256508.
%H Paul Tek, <a href="/A256513/b256513.txt">Table of n, a(n) for n = 1..300</a>
%F a(n+1) = A256508^n(n+1) for any n>=0 (where A256508^n denotes the n-th iterate of A256508).
%e a(3) = A256508^2(3) = A256508(A256508(3)) = A256508(6) = 9.
%Y Cf. A256508.
%K nonn
%O 1,2
%A _Paul Tek_, Apr 01 2015