|
%I #5 Jan 30 2015 06:34:54
%S 4,8,22,103,1045,33781,6208815,15470810960,1924285995519778,
%T 84412046357073810845036,24524866000840265443624861229739287,
%U 3840696279681724751490160062668766360564070043725605,238020820035391513516910494940635409432084649486247633125762760898691133120625
%N a(n) = floor(a(n-1)^(3/2)), a(1) = 4.
%F a(n) ~ c^((3/2)^n), where c = 2.4979223179189793375148967824709800001224474904593996103376... .
%t RecurrenceTable[{a[1]==4,a[n]==Floor[a[n-1]^(3/2)]},a,{n,1,15}]
%Y Cf. A254403.
%K nonn,easy
%O 1,1
%A _Vaclav Kotesovec_, Jan 30 2015
|
