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A254117 Permutation of natural numbers: a(n) = A254104(A249746(1+n)-1). 3

%I #10 Jun 06 2017 10:33:24

%S 1,2,3,6,5,4,10,7,11,21,9,31,16,15,23,27,63,13,43,8,19,53,14,37,45,47,

%T 95,26,22,17,511,127,12,91,39,18,85,62,29,2047,30,38,111,20,54,75,42,

%U 55,157,35,46,174,25,79,24,59,77,303,123,94,78,167,87,223,61,103,699,191,41,107,183,125,431,28,71,84,60,93,110,767,51

%N Permutation of natural numbers: a(n) = A254104(A249746(1+n)-1).

%H Antti Karttunen, <a href="/A254117/b254117.txt">Table of n, a(n) for n = 1..8192</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%F a(n) = A254104(A249746(1+n)-1).

%F a(n) = (A254115((2*n)+1)-1) / 2. [Obtained also from the odd bisection of A254115.]

%o (Scheme, two versions)

%o (define (A254117 n) (A254104 (+ -1 (A249746 (+ 1 n)))))

%o (define (A254117 n) (/ (+ -1 (A254115 (+ 1 n n))) 2))

%o (Python)

%o from sympy import factorint, nextprime

%o from operator import mul

%o def a048673(n):

%o f = factorint(n)

%o return 1 if n==1 else (1 + reduce(mul, [nextprime(i)**f[i] for i in f]))/2

%o def a254104(n):

%o if n==0: return 0

%o if n%3==0: return 1 + 2*a254104(2*n/3 - 1)

%o elif n%3==1: return 1 + 2*a254104(2*(n - 1)/3)

%o else: return 2*a254104((n - 2)/3 + 1)

%o def a254115(n): return a254104(a048673(n))

%o def a(n): return (a254115(2*n + 1) - 1)/2 # _Indranil Ghosh_, Jun 06 2017

%Y Inverse: A254118.

%Y Other related permutations: A249746, A254104, A254115.

%K nonn

%O 1,2

%A _Antti Karttunen_, Feb 05 2015

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Last modified August 3 17:10 EDT 2024. Contains 374895 sequences. (Running on oeis4.)