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%I #9 Mar 07 2015 14:19:22
%S 0,1,1,2,1,1,1,4,1,3,2,6,1,2,3,8,1,5,1,10,2,1,4,12,1,7,5,14,3,4,2,16,
%T 1,9,6,18,1,3,7,20,2,11,3,22,4,6,8,24,1,13,9,26,5,2,1,28,3,15,10,30,2,
%U 8,11,32,1,17,4,34,6,5,12,36,1,19,13,38,7,10,5,40,2,21,14,42,3,1,15,44,4,23,2,46,8,12,16,48,1,25,17,50,9,7,6,52,5,27,18,54,1,14,19,56,3,29,7,58,10,4,20,60,2
%N a(n) = A126760(A007494(n)).
%H Antti Karttunen, <a href="/A254048/b254048.txt">Table of n, a(n) for n = 0..19683</a>
%F a(n) = A126760(A007494(n)).
%F Other identities:
%F a(4n) = A126760(n).
%F a(4n+1) = A126760(3n+1).
%F a(4n+2) = A126760(2n+1) = A253887(n+1).
%F a(4n+3) = 2n+2.
%F For all n >= 1, a(n) = A126760(A139391(n)). [Conjecture. The proof should be easy. Holds at least up to n = 2^25 = 33554432.]
%o (Scheme) (define (A254048 n) (A126760 (A007494 n)))
%Y Cf. A006370, A007494, A126760, A139391, A253887, A254102.
%K nonn
%O 0,4
%A _Antti Karttunen_, Jan 28 2015