A250422 Number of length 5+1 0..n arrays with the sum of the minimum of each adjacent pair multiplied by some arrangement of +-1 equal to zero

36, 335, 1693, 5982, 16790, 39916, 84094, 161350, 287910, 484353, 776742, 1196504, 1781894, 2577507, 3636138, 5017850, 6792317, 9037401, 11842016, 15304097, 19534144, 24652517, 30793639, 38102572, 46740025, 56878092, 68706116, 82425513

Offset

1,1

Comments

Row 5 of A250419

Links

R. H. Hardin, Table of n, a(n) for n = 1..206

Formula

Empirical: a(n) = a(n-1) +a(n-2) +a(n-3) -4*a(n-5) -a(n-6) -a(n-7) +4*a(n-8) +4*a(n-9) -a(n-10) -a(n-11) -4*a(n-12) +a(n-14) +a(n-15) +a(n-16) -a(n-17)

Empirical for n mod 12 = 0: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (689/288)*n^2 + (211/72)*n + 1

Empirical for n mod 12 = 1: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (3449/1152)*n^2 + (4903/3456)*n + (74825/20736)

Empirical for n mod 12 = 2: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (689/288)*n^2 + (395/144)*n + (1633/1296)

Empirical for n mod 12 = 3: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (3449/1152)*n^2 + (1765/1152)*n + (953/256)

Empirical for n mod 12 = 4: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (689/288)*n^2 + (649/216)*n + (92/81)

Empirical for n mod 12 = 5: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (3449/1152)*n^2 + (1549/1152)*n + (76105/20736)

Empirical for n mod 12 = 6: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (689/288)*n^2 + (395/144)*n + (17/16)

Empirical for n mod 12 = 7: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (3449/1152)*n^2 + (5551/3456)*n + (80009/20736)

Empirical for n mod 12 = 8: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (689/288)*n^2 + (211/72)*n + (97/81)

Empirical for n mod 12 = 9: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (3449/1152)*n^2 + (1549/1152)*n + (889/256)

Empirical for n mod 12 = 10: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (689/288)*n^2 + (1217/432)*n + (1553/1296)

Empirical for n mod 12 = 11: a(n) = (16771/3456)*n^5 - (18673/6912)*n^4 + (133891/5184)*n^3 + (3449/1152)*n^2 + (1765/1152)*n + (81289/20736)

Example

Some solutions for n=6
..3....5....3....3....4....4....4....2....2....2....3....6....2....5....0....5
..5....1....0....4....2....2....6....1....4....0....2....2....2....4....2....4
..4....2....2....6....5....1....1....0....0....0....2....2....3....2....5....6
..1....0....2....1....3....1....6....2....0....5....3....6....0....4....0....1
..3....0....3....1....6....5....6....5....2....3....4....1....6....2....4....2
..1....3....0....3....2....3....0....1....5....6....1....6....4....3....2....4

Crossrefs

Sequence in context: A219004 A053136 A000821 * A223307 A244795 A222492

Adjacent sequences: A250419 A250420 A250421 * A250423 A250424 A250425

Keyword

nonn

Author

R. H. Hardin, Nov 22 2014

Status

approved