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A250373
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T(n,k)=Number of length n+6 0..k arrays with every seven consecutive terms having the maximum of some three terms equal to the minimum of the remaining four terms
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15
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93, 1382, 151, 8964, 3096, 252, 37385, 24566, 7168, 424, 118621, 119235, 69984, 16798, 714, 312578, 428421, 396745, 202184, 39471, 1198, 720112, 1256106, 1616636, 1340867, 584904, 92497, 1996, 1498569, 3179756, 5272892, 6202712, 4530981
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OFFSET
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1,1
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COMMENTS
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Table starts
...93....1382......8964......37385......118621.......312578.......720112
..151....3096.....24566.....119235......428421......1256106......3179756
..252....7168.....69984.....396745.....1616636......5272892.....14647808
..424...16798....202184....1340867.....6202712.....22517208.....68640720
..714...39471....584904....4530981....23761098.....95876627....320301600
.1198...92497...1680652...15139945....89632970....400455241...1460936344
.1996..215345...4766064...49559017...328905292...1616234585...6398378176
.3292..496659..13262440..157464877..1159359444...6203069791..26383796944
.5464.1156281..37406584..510276209..4200082656..24676972585.113797974816
.9138.2712668.106733108.1679222839.15510937222.100433289066.503805257096
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LINKS
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FORMULA
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Empirical for column k:
k=1: [linear recurrence of order 56]
Empirical for row n:
n=1: [polynomial of degree 6]
n=2: [polynomial of degree 7]
n=3: [polynomial of degree 8]
n=4: [polynomial of degree 9]
n=5: [polynomial of degree 10]
n=6: [polynomial of degree 11]
n=7: [polynomial of degree 11]
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EXAMPLE
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Some solutions for n=3 k=4
..1....0....1....0....1....0....0....1....1....1....0....0....0....1....0....0
..1....2....1....4....1....3....2....0....1....1....2....2....2....1....0....2
..2....1....4....2....3....4....1....4....0....3....1....1....1....0....2....4
..2....1....2....0....1....0....2....0....1....1....1....1....2....2....3....2
..1....3....4....2....3....1....1....0....2....2....3....4....3....3....0....2
..0....0....3....3....0....4....0....4....4....1....2....1....3....1....0....1
..0....3....2....4....1....1....2....0....0....0....1....0....2....4....0....2
..1....0....1....1....0....1....1....0....1....1....0....3....2....1....0....0
..1....1....0....2....4....2....0....3....4....0....2....2....4....1....2....3
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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