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A249558
a(a(n)) is a triangular number.
0
1, 3, 6, 2, 7, 10, 15, 9, 21, 28, 12, 36, 14, 45, 55, 17, 66, 19, 78, 22, 91, 105, 24, 120, 26, 136, 29, 153, 171, 31, 190, 33, 210, 35, 231, 253, 38, 276, 40, 300, 42, 325, 44, 351, 378, 47, 406, 49, 435, 51, 465, 53, 496, 56, 528, 561
OFFSET
1,2
COMMENTS
To build T: always use the smallest integer not yet present in T and not leading to a contradiction.
All triangular numbers appear in their natural order.
Density of T: it appears that more than 50% of the terms are triangular.
Arie Groeneveld computed a million terms in less than 1.5 seconds using the language J.
REFERENCES
Eric Angelini, Postings to Sequence Fans Mailing List, Mar 02 2011 and Mar 03 2011.
EXAMPLE
T = 1,... meaning that the first term of T is a triangular number (true)
The next term can't be 2 as '2' would mean that the second term of T is a triangular term -- which is false, 2 is not a triangular number -- see A000217
Then:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,
We have to put a triangular number 't' in third position:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,t,
Thus:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,
Thus:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,* * t
Now we need to replace the first star with "the smallest integer not yet present in T and not leading to a contradiction":
Thus:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,2,* t
Next star is replaced by "the smallest etc." which can't be 4, 5 or 6 -- thus 7 (the 4th term of T is not a triangular number, the 5th neither -- as it would be '5' -- and '6' is already in T):
Thus:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,2,7,t
and:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,2,7,t t
We replace the next two 't' with two triangular numbers:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,2,7,10,15,
and mark accordingly the 10th and 15th term of T with 't':
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,2,7,10,15, t t
The next 'hole' we have to fill in T is the 8th; we put '9':
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,2,7,10,15,9, t t
and we add accordingly a 't' in 9th position:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,2,7,10,15,9,t, t t
Now two more triangular numbers:
n : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
T = 1,3,6,2,7,10,15,9,21,28, t
... etc.
CROSSREFS
Cf. A000217.
Sequence in context: A186706 A169749 A169750 * A072007 A078783 A273465
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Nov 01 2014
STATUS
approved