Empirical: a(n) = 4*a(n-1) -6*a(n-2) +5*a(n-3) -4*a(n-4) +3*a(n-5) -2*a(n-6) +2*a(n-7) -2*a(n-9) +2*a(n-10) -3*a(n-11) +4*a(n-12) -5*a(n-13) +6*a(n-14) -4*a(n-15) +a(n-16)
Also a degree 6 polynomial plus a degree 0 quasipolynomial with period 60, the first 12 being:
Empirical for n mod 60 = 0: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n
Empirical for n mod 60 = 1: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n + (547/60)
Empirical for n mod 60 = 2: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n - (124/15)
Empirical for n mod 60 = 3: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n - (183/20)
Empirical for n mod 60 = 4: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n + (472/15)
Empirical for n mod 60 = 5: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n - (425/12)
Empirical for n mod 60 = 6: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n + (156/5)
Empirical for n mod 60 = 7: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n - (821/60)
Empirical for n mod 60 = 8: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n + (344/15)
Empirical for n mod 60 = 9: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n - (879/20)
Empirical for n mod 60 = 10: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n + (80/3)
Empirical for n mod 60 = 11: a(n) = n^6 + (24/5)*n^5 + (51/4)*n^4 + (49/3)*n^3 + 13*n^2 + 5*n + (1547/60)
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