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%I #6 Dec 12 2014 20:31:30
%S 62,606,122,3492,1572,240,13580,12156,4120,472,40950,59720,42400,
%T 10834,928,104562,217170,263156,147984,28500,1824,235196,655352,
%U 1154444,1161050,516652,74886,3586,480912,1699092,4116620,6143828,5126096
%N T(n,k)=Number of length n+5 0..k arrays with no six consecutive terms having five times any element equal to the sum of the remaining five
%C Table starts
%C ....62.....606......3492......13580........40950........104562.........235196
%C ...122....1572.....12156......59720.......217170........655352........1699092
%C ...240....4120.....42400.....263156......1154444.......4116620.......12297972
%C ...472...10834....147984....1161050......6143828......25889916.......89105036
%C ...928...28500....516652....5126096.....32715172.....162930700......645979544
%C ..1824...74886...1804128...22639594....174242716....1025679026.....4684420552
%C ..3586..196346...6301554...99998070....928056514....6457498056....33973205930
%C ..7050..515066..22009836..441725882...4943294814...40657829724...246394508200
%C .13860.1352304..76884550.1951405680..26331473568..255999677748..1787038582186
%C .27248.3552428.268579888.8621117794.140263427946.1611927429578.12961135262872
%H R. H. Hardin, <a href="/A249530/b249530.txt">Table of n, a(n) for n = 1..468</a>
%F Empirical for column k:
%F k=1: a(n) = a(n-1) +a(n-2) +a(n-3) +a(n-4) +a(n-5)
%F k=2: [order 92]
%F Empirical for row n:
%F n=1: [linear recurrence of order 16; also a polynomial of degree 6 plus a quasipolynomial of degree 0 with period 60]
%e Some solutions for n=3 k=4
%e ..1....1....0....1....0....1....1....0....1....0....0....1....0....0....1....1
%e ..0....1....0....3....3....4....4....4....0....0....0....3....2....4....2....2
%e ..1....4....0....3....0....0....1....0....3....3....1....0....0....4....3....0
%e ..2....4....1....1....2....2....1....0....4....1....0....1....4....1....0....3
%e ..2....0....3....1....0....1....0....0....2....1....1....1....1....4....2....4
%e ..4....0....0....3....4....0....3....2....4....4....1....1....0....0....1....3
%e ..2....1....1....2....0....2....3....2....2....3....1....1....1....1....1....3
%e ..0....3....4....1....0....2....0....2....4....0....4....1....1....1....4....0
%Y Column 1 is A135493(n+5)
%K nonn,tabl
%O 1,1
%A _R. H. Hardin_, Oct 31 2014
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