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T(n,k)=Number of length n+4 0..k arrays with no five consecutive terms having four times any element equal to the sum of the remaining four
13

%I #6 Dec 12 2014 20:45:46

%S 30,190,58,860,464,112,2640,2948,1140,216,6730,11260,10124,2802,416,

%T 14730,35322,48180,34832,6872,802,29060,91160,185982,206428,119932,

%U 16800,1546,52900,207760,565516,980718,884728,412972,41084,2980,90390,429364

%N T(n,k)=Number of length n+4 0..k arrays with no five consecutive terms having four times any element equal to the sum of the remaining four

%C Table starts

%C ....30....190......860.......2640........6730........14730.........29060

%C ....58....464.....2948......11260.......35322........91160........207760

%C ...112...1140....10124......48180......185982.......565516.......1488294

%C ...216...2802....34832.....206428......980718......3512232......10671554

%C ...416...6872...119932.....884728.....5174842.....21824440......76550058

%C ...802..16800...412972....3791504....27309702....135637752.....549183692

%C ..1546..41084..1422232...16249428...144140836....843025344....3940066010

%C ..2980.100590..4898776...69646680...760833398...5239822940...28268238072

%C ..5744.246378.16874830..298527530..4016197550..32568952752..202814997034

%C .11072.603406.58131580.1279613894.21200828116.202440565098.1455140474848

%H R. H. Hardin, <a href="/A249466/b249466.txt">Table of n, a(n) for n = 1..2019</a>

%F Empirical for column k:

%F k=1: a(n) = a(n-1) +a(n-2) +a(n-3) +a(n-4)

%F k=2: [order 37]

%F Empirical for row n:

%F n=1: [linear recurrence of order 11; also a polynomial of degree 5 plus a constant quasipolynomial with period 12]

%e Some solutions for n=3 k=4

%e ..0....2....0....1....2....3....2....3....3....3....4....3....4....4....2....3

%e ..0....0....1....0....0....0....4....0....0....4....3....4....3....2....4....2

%e ..2....0....2....2....1....4....3....0....0....4....4....0....2....0....1....2

%e ..3....0....3....0....1....0....2....4....3....3....1....3....3....0....4....0

%e ..3....2....0....3....2....3....0....0....4....4....2....4....0....2....1....1

%e ..3....2....0....1....0....4....0....3....2....3....4....2....0....2....3....2

%e ..3....4....0....2....3....1....4....2....3....3....0....4....2....4....2....1

%Y Column 1 is A135492(n+4)

%Y Column 2 is A248995

%K nonn,tabl

%O 1,1

%A _R. H. Hardin_, Oct 29 2014