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a(n) = A249151(n) - n.
7

%I #7 Nov 02 2014 18:14:33

%S 1,0,0,-2,0,-3,0,-6,-6,-5,0,-4,0,-7,-10,-14,0,-15,0,-15,-14,-11,0,-12,

%T -20,-13,-24,-21,0,-4,0,-30,-22,-17,-28,1,0,-19,-26,1,0,-35,0,-33,-21,

%U -23,0,-28,-42,-45,-34,-39,0,-51,-44,-20,-38,-29,0,-12,0,-31,1,-62,-52,-55,0,-51,-46,-20,0,-30,0

%N a(n) = A249151(n) - n.

%C It seems that A006093 gives the positions of zeros.

%H Antti Karttunen, <a href="/A249431/b249431.txt">Table of n, a(n) for n = 0..4096</a>

%F a(n) = A249151(n) - n.

%o (Scheme) (definec (A249431 n) (- (A249151 n) n))

%Y A249433 and A249434 give the positions of negative and nonnegative values, respectively.

%Y A249430 gives the position where +n appears for the first time, A249432 the positions of records of positive values.

%Y Cf. A006093, A249151.

%K sign

%O 0,4

%A _Antti Karttunen_, Nov 02 2014