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%I #4 Sep 16 2014 08:06:36
%S 0,40,200,760,2280,5640,12120,23800,43040,73840,120240,188040,283680,
%T 415840,593240,827680,1131240,1519200,2007240,2614720,3361280,4271080,
%U 5368320,6681840,8241120,10080760,12235400,14745640,17652360,21002520
%N Number of length 1+4 0..n arrays with no disjoint pairs in any consecutive five terms having the same sum
%C Row 1 of A247404
%H R. H. Hardin, <a href="/A247405/b247405.txt">Table of n, a(n) for n = 1..210</a>
%F Empirical: a(n) = 3*a(n-1) -2*a(n-2) -a(n-3) +a(n-4) -2*a(n-5) +4*a(n-6) -2*a(n-7) +a(n-8) -a(n-9) -2*a(n-10) +3*a(n-11) -a(n-12)
%F Empirical for n mod 12 = 0: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 34*n
%F Empirical for n mod 12 = 1: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 19*n + 20
%F Empirical for n mod 12 = 2: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 34*n + 40
%F Empirical for n mod 12 = 3: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 19*n + 80
%F Empirical for n mod 12 = 4: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 34*n
%F Empirical for n mod 12 = 5: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 19*n + 60
%F Empirical for n mod 12 = 6: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 34*n
%F Empirical for n mod 12 = 7: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 19*n + 80
%F Empirical for n mod 12 = 8: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 34*n + 40
%F Empirical for n mod 12 = 9: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 19*n + 20
%F Empirical for n mod 12 = 10: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 34*n
%F Empirical for n mod 12 = 11: a(n) = n^5 - 5*n^4 + 30*n^3 - 65*n^2 + 19*n + 120
%e Some solutions for n=6
%e ..2....6....3....2....0....0....6....0....5....6....5....4....4....6....5....1
%e ..4....2....0....0....5....5....6....5....6....6....4....4....2....2....0....0
%e ..1....1....6....5....6....6....1....6....3....3....4....1....6....6....6....6
%e ..1....6....6....4....0....3....6....0....5....5....0....4....1....1....2....0
%e ..1....3....6....0....2....6....0....3....1....6....4....5....1....0....5....3
%K nonn
%O 1,2
%A _R. H. Hardin_, Sep 16 2014
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