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A246085 Paradigm shift sequence for (1,3) production scheme with replacement. 9

%I #9 Nov 22 2016 11:13:01

%S 1,2,3,4,5,6,7,8,9,10,11,12,13,14,16,18,21,24,27,30,33,36,40,44,48,54,

%T 63,72,81,90,99,108,120,132,144,162,189,216,243,270,297,324,360,396,

%U 432,486,567,648,729,810,891,972,1080,1188,1296,1458,1701,1944,2187,2430,2673,2916,3240,3564,3888,4374,5103,5832,6561,7290,8019,8748,9720,10692

%N Paradigm shift sequence for (1,3) production scheme with replacement.

%C This sequence is the solution to the following problem: "Suppose you have the choice of using one of three production options: apply a simple incremental action, bundle existing output as an integrated product (which requires p=1 steps), or implement the current bundled action (which requires q=3 steps). The first use of a novel bundle erases (or makes obsolete) all prior actions. How large an output can be generated in n time steps?"

%C 1. A production scheme with replacement R(p,q) eliminates existing output following a bundling action, while an additive scheme A(p,q) retains the output. The schemes correspond according to A(p,q)=R(p-q,q), with the replacement scheme serving as the default presentation.

%C 2. This problem is structurally similar to the Copy and Paste Keyboard problem: Existing sequences (A178715 and A193286) should be regarded as Paradigm-Shift Sequences with production schemes R(1,1) and R(2,1) with replacement, respectively.

%C 3. The ideal number of implementations per bundle, as measured by the geometric growth rate (p+zq root of z), is z = 3.

%C 4. All solutions will be of the form a(n) = (qm+r) * m^b * (m+1)^d.

%H Colin Barker, <a href="/A246085/b246085.txt">Table of n, a(n) for n = 1..1000</a>

%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,0,0,3).

%F a(n) = (qd+r) * d^(C-R) * (d+1)^R, where r = (n-Cp) mod q, Q = floor( (R-Cp)/q ), R = Q mod (C+1), and d = floor ( Q/(C+1) ).

%F a(n) = 3*a(n-10) for all n >= 25.

%F G.f.: x*(1 +2*x +3*x^2 +4*x^3 +5*x^4 +6*x^5 +7*x^6 +8*x^7 +9*x^8 +10*x^9 +8*x^10 +6*x^11 +4*x^12 +2*x^13 +x^14 +x^22 +2*x^23) / (1 -3*x^10). - _Colin Barker_, Nov 22 2016

%o (PARI) Vec(x*(1 +2*x +3*x^2 +4*x^3 +5*x^4 +6*x^5 +7*x^6 +8*x^7 +9*x^8 +10*x^9 +8*x^10 +6*x^11 +4*x^12 +2*x^13 +x^14 +x^22 +2*x^23) / (1 -3*x^10) + O(x^100)) \\ _Colin Barker_, Nov 22 2016

%Y Paradigm shift sequences with q=3: A029747, A029750, A246077, A246081, A246085, A246089, A246093, A246097, A246101.

%Y Paradigm shift sequences with p=1: A178715, A246084, A246085, A246086, A246087.

%K nonn,easy

%O 1,2

%A _Jonathan T. Rowell_, Aug 13 2014

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