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%I #23 Jul 21 2014 09:31:18
%S 1,2,2,8,8,8,64,64,64,64,1024,1024,1024,1024,1024,32768,32768,32768,
%T 32768,32768,32768,2097152,2097152,2097152,2097152,2097152,2097152,
%U 2097152,268435456,268435456,268435456,268435456,268435456,268435456,268435456,268435456
%N Repeat 2^(n*(n+1)/2) n+1 times.
%C For a(n), the successive exponents of 2 are 0, 1, 1, 3, 3, 3,... = A057944(n).
%F a(n) = 2^n/A059268(n).
%F T(n, k) = 2^(n*(n+1)/2), 0 <= k <= n. - _Michel Marcus_, Jul 17 2014
%e n+1 times repeated 2^(n*(n+1)/2)= 1, 2, 8, 64, 1024,... = A139685(n).
%e By the formula: a(0)=1/1=1, a(1)=2/1=2, a(2)=4/2=2, a(3)=8/1=8, a(4)=16/2=8,...
%e As triangle:
%e 1,
%e 2, 2,
%e 8, 8, 8,
%e 64, 64, 64, 64,
%e 1024, 1024, 1024, 1024, 1024,
%e etc.
%e Row sums: 1, 4, 24, 256,... = A095340.
%t Table[2^(n*(n+1)/2), {n, 0, 7}, {n+1}] // Flatten (* _Jean-François Alcover_, Jul 15 2014 *)
%Y Cf. A000079, A006125, A057944, A059268, A095340, A123903, A139685.
%K nonn,tabl
%O 0,2
%A _Paul Curtz_, Jul 14 2014
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