%I #3 Jul 23 2014 16:26:58
%S 0,0,0,1,-1,0,1,1,-2,0,0,1,0,0,1,1,-3,0,0,1,-1,0,1,1,-1,0,0,1,0,0,1,1,
%T -4,0,0,1,-1,0,1,1,-2,0,0,1,0,0,1,1,-2,0,0,1,-1,0,1,1,-1,0,0,1,0,0,1,
%U 1,-5,0,0,1,-1,0,1,1,-2,0,0,1,0,0,1,1,-3,0,0,1,-1,0,1,1,-1,0,0,1,0,0,1
%N G.f.: Sum_{k>=0} t^3/((1+t)*(1+t^2)), where t=x^(2^k).
%Y Partial sums give A014081.
%K sign
%O 0,9
%A _N. J. A. Sloane_, Jul 23 2014