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a(1) = 2; for n>1, a(n) = product of digits of (a(n-1)^2).
0

%I #19 Aug 23 2017 14:35:14

%S 2,4,6,18,24,210,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

%T 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,

%U 0,0,0,0,0,0

%N a(1) = 2; for n>1, a(n) = product of digits of (a(n-1)^2).

%e 6 is in the sequence because 4^2=16 and 6*1=6.

%e 18 is in the sequence because 6^2=36 and 3*6=18.

%e Other similar sequences, starting from 3, 5 and 7, respectively:

%e . 3, 9, 8, 24, 210, 0 (0 continued);

%e . 5, 10, 0;

%e . 7, 36, 108, 144, 0.

%t a[1] = 2; a[n_] := a[n] = Times @@ IntegerDigits[a[n - 1]^2]; Array[a, 100] (* _Jean-François Alcover_, May 29 2014 *)

%t NestList[Times@@IntegerDigits[#^2]&,2,80] (* _Harvey P. Dale_, Aug 23 2017 *)

%Y Cf. A163522.

%K nonn,base,easy

%O 1,1

%A _Vincenzo Librandi_, May 29 2014