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For any number m there is a number k such that m-k^3 is congruent mod 96 to one of these 12 numbers.
0

%I #9 May 29 2014 11:47:12

%S 6,12,18,24,30,36,48,54,60,66,78,84

%N For any number m there is a number k such that m-k^3 is congruent mod 96 to one of these 12 numbers.

%C Arises in studying Waring's problem for cubes.

%D Edmund Landau, Handbuch der Lehre von der Verteilung der Primzahlen, Chelsea Publishing, NY 1953, p. 356, Hilfssatz 2.

%e For example, if m = 0 we take k = 18, 0 - 18^3 = -5832 = 24 mod 96 and 24 is a member.

%K nonn,fini,full

%O 1,1

%A _N. J. A. Sloane_, May 29 2014