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%I #6 May 29 2014 12:07:55
%S 0,2,3,5,6,7,8,9,11,12,13,15,16,17,18,19,20,21,23,24,25,27,28,29,30,
%T 31,32,33,35,37,39,40,41,42,43,44,45,47,49,51,52,53,54,55,56,57,59,61,
%U 63,64,65,66,67,68,69,70,71,72,73,75,76,77,78,79,80,81,83
%N Possible values of A242480(n) in increasing order.
%C A242480(n) = (n*(n+1)/2) mod n + sigma(n) mod n + antisigma(n) mod n = A142150(n) + A054024(n) + A229110(n) = (A000217(n) mod n) + (A000203(n) mod n) + (A024816(n) mod n).
%C Supersequence of odd numbers > 1. Complement of A242486.
%e 16 is in the sequence because there is a number m such that A242480(m) = 16; m = 8.
%Y Cf. A242480, A242481, A242482, A242483, A242484, A242486.
%K nonn
%O 1,2
%A _Jaroslav Krizek_, May 27 2014
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